Lecture 13: Global Illumination & Path Tracing (43)
daniel-man
I was initially very confused by the statement on the previous slide that (I - K)^(-1) = 1 / (I - K), since I couldn't see how the "bastardized algebra" of treating the inverse as a reciprocal was valid. However, walking through the short proof on this slide made it clear to me that the Neumann series was a mathematically correct substitute for the inverse of (I - K).
I was initially very confused by the statement on the previous slide that (I - K)^(-1) = 1 / (I - K), since I couldn't see how the "bastardized algebra" of treating the inverse as a reciprocal was valid. However, walking through the short proof on this slide made it clear to me that the Neumann series was a mathematically correct substitute for the inverse of (I - K).