Lecture 10: Ray Tracing Acceleration (17)
jerryzhucs21

Instead of splitting the space within the image equally each time, i wonder if you can split the image in half by the number of objects within the space using some type of a heuristic. For example, what if almost all objects were in section 4? Also, would using a heuristic be computationally efficient?

ZizhengTai

This is similar to the mipmap structure which means it's space efficient!

yuhany1024

I wonder why we only split either the left or right node, rather than split both? For example, in this slide, does it mean that the number of objects in 1 is almost same with the sum of all object from 2 to 5?

You must be enrolled in the course to comment