If it is perfect, why isn't the light bouncing off as bright?
alexkassil
Also, if this was a glossy surface instead, would we see a cone of light rays being reflected?
daniswords
I think that perfect specular reflection has to do with the angles on each side of the normal being equivalent (like on the next slide)
jerry-jiao
adding onto alex's question, would a potential explanation for that be that even if the surface is perfectly smooth and produces a reflection where w_in and w_out are the same, the nature of the material itself and what it's made of will affect how much light is reflected? for example some of the photons may travel through the material (even if we can't see it) or if the material itself will absorb some of the light?
If it is perfect, why isn't the light bouncing off as bright?
Also, if this was a glossy surface instead, would we see a cone of light rays being reflected?
I think that perfect specular reflection has to do with the angles on each side of the normal being equivalent (like on the next slide)
adding onto alex's question, would a potential explanation for that be that even if the surface is perfectly smooth and produces a reflection where w_in and w_out are the same, the nature of the material itself and what it's made of will affect how much light is reflected? for example some of the photons may travel through the material (even if we can't see it) or if the material itself will absorb some of the light?