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Lecture 7: Intro to Geometry, Splines, and Bezier Curves (38)
phoebeli23

I'm a bit confused here. What do these basis functions have in common and how are they combined to get the final solution?

Staffajayjain

@phoebeli23 the inputs to cubic hermite interpolation, h0,h1,h2,h3h_0, h_1, h_2, h_3, are coefficients for the Hermite basis functions. So, given hih_i, the interpolating polynomial is P(t)=h0H0(t)+h1H1(t)+h2H2(t)+h3H3(t)P(t) = h_0 H_0(t) + h_1 H_1(t) + h_2 H_2(t) + h_3 H_3(t). That's really convenient!

phoebeli23

That makes a lot of sense, thank you

nobugnohair

Representation of a polynomial with several base functions reminds me of Fourier Transforms. Are these bases functions reused in all cases like sines and cosines in Fourier Transforms? Are there exceptions?

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