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Lecture 8: Mesh Representations and Geometry Processing (67)
joshua16266261

Why do we do uTQuu^T Qu instead of (uTv)2(u^T v)^2, because to me, it seems like performing uTQuu^T Q u takes more operations than performing (uTv)2(u^T v)^2?

thecatherinehuang

I think we do (uTv)2(u^Tv)^2. The :=uTQu:= u^TQu is just showing the equivalence to the value we want to calculate.

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