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Lecture 21: Image Sensors (12)

Is this saying that the ejected electrons here are a result of the incident photons. I'm not sure what this image is really describing.


Yea, I believe that's basically what the photoelectric effect can be boiled down to. From what I understand, the energy/how powerful the light (the photons) that gets shone on the metal is, the higher energy the electrons emitted are. Thus, based on the light incident to the metal we get a corresponding reaction (assuming that we meet a threshold) from the emission.


According to the Wikipedia article for the photoelectric effect (, an electron must receive a certain threshold of energy to be ejected from the metal. If insufficient energy is distributed to the electron, it will not be removed from the metal.

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