Lecture 4: Transforms (82)
jeshlee121

There was a question in lecture about why we can't just do: q = [d/z 0 0 0; 0 d/z 0 0; 0 0 d/z 0; 0 0 0 1] [x; y; z; 1] = [xd/z; xd/z; d; 1]

jeshlee121

When I asked Ren, he explained that the above transformation isn't linear since it relies on the variable z, which is why we wouldn't do this.

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