There was a question in lecture about why we can't just do: q = [d/z 0 0 0; 0 d/z 0 0; 0 0 d/z 0; 0 0 0 1] [x; y; z; 1] = [xd/z; xd/z; d; 1]
When I asked Ren, he explained that the above transformation isn't linear since it relies on the variable z, which is why we wouldn't do this.
There was a question in lecture about why we can't just do: q = [d/z 0 0 0; 0 d/z 0 0; 0 0 d/z 0; 0 0 0 1] [x; y; z; 1] = [xd/z; xd/z; d; 1]
When I asked Ren, he explained that the above transformation isn't linear since it relies on the variable z, which is why we wouldn't do this.