A word of caution here: Both edges mc and mb are treated as 'old' in the spligging phase of upsampling operation, even though one of those edges must be new. Referring to slide 41, look at how both of the edges that are components of what used to be an old edge is marked black instead of blue.
john-b-yang
I understand on the left hand side, there are two half edges (left and right) triangles. After the split, are there 4 or 6 half edges? In other words, are the original triangles retained or discarded?
Jordanwyli
@john-b-yang, I think the original triangles can be thought as if they were halved, and you would add an additional two half edges to the left triangle.
jchen12197
How come when we perform edge splitting, we need to create 3 new edges (am, dm, bm), but when we implement loop subdivision, we mark bm as an old edge?
A word of caution here: Both edges mc and mb are treated as 'old' in the spligging phase of upsampling operation, even though one of those edges must be new. Referring to slide 41, look at how both of the edges that are components of what used to be an old edge is marked black instead of blue.
I understand on the left hand side, there are two half edges (left and right) triangles. After the split, are there 4 or 6 half edges? In other words, are the original triangles retained or discarded?
@john-b-yang, I think the original triangles can be thought as if they were halved, and you would add an additional two half edges to the left triangle.
How come when we perform edge splitting, we need to create 3 new edges (am, dm, bm), but when we implement loop subdivision, we mark bm as an old edge?
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