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Lecture 8: Meshes and Geometry Processing (37)
john-b-yang

I know this is probably implied and not entirely necessary, but it really helped me to just write out the calculations for each of the numbers so I'll just leave it here. To get 1/16, u = 3 / 8n where n = 6 so 3 / (8 * 6) = 1/16 To get 10/16, 1 - n*u so 1 - (6 * 1/16) = 10/16

john-b-yang

Just realized this was communicated in lecture too, apologies if this is a bit redundant.

jchen12197

Thanks for this explanation on how to get 1/16! For the last project, I took the values 1/8 and u = 3/8n or 3/16 as given, but I'm not really sure where those numbers came from either. Could someone specify?

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