Lecture 12: Monte Carlo Integration (29)
rileylyman184

Something interesting I noticed is that calculating the monte carlo estimator for a 1D function is equivalent to finding the area of a 2D rectangle and finding the estimator for a 3D function is equivalent to finding the volume of a 4D hypercube. Generalizing this, we can see that integrating any n dimensional function will be equivalent to finding the volume of a n+1 dimensional hypercube. This is because the n axes of the function are like the width and length, etc, of the cube, and the actual value of the function is the last missing piece that adds another dimension.

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