The rays that don't hit the light source would have a dark area, so trying to integrate over it would result in a lot of noise.
@ivyn This is why we should integrate only over the area of the light, because the integrated result will be less noisy?
The rays that don't hit the light source would have a dark area, so trying to integrate over it would result in a lot of noise.
@ivyn This is why we should integrate only over the area of the light, because the integrated result will be less noisy?